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Interesting facts
If [V] is the function of the equation
so...
[V] = v + 1
Then, [V]1 = (v + 1) + 1, and [V]2 = ((v + 1) + 1) + 1.
Assuming U is the initial value of v then... that means
[V]t = u + t + 1
Also, in the equation...
[V] = xv
[V]t = ux^t
And...
[V] = xv + b
[V]t = ux^t + bx^(t - 1)+ bx^(t - 2) + .... + b
This is math that I've been doing on my own
So, if you replace "v" with "ans" on your calculator.
And the initial value of "Ans" is 5, and you type in
2Ans + 3
and you click equals 3 times.
Using that formula I just gave, that would be the same as
5 x 3^3 + 3 x 5^2 + 3 x 5 + 3