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Author Topic: The Wondrous Sequence (Competition)!  (Read 3528 times)

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Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #30 on: February 27, 2014, 08:04:46 AM »
Wow, my victories are so fleeting!


999.997


 @.@
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Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #31 on: February 27, 2014, 01:03:47 PM »
Poor trixie D:

That's only a 6 digit number :O Lets see what it gives

113 steps, yeah, I'd go for higher digit numbers xD

However, 113 steps is large for a 6 digit number, so perhaps guesses in the 999,000,000-1,000,000,000 domain will hold a lot of steps?
« Last Edit: February 27, 2014, 01:07:48 PM by anoni »
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(int(e-x^2, x = -infinity..infinity))2 = Pi


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Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #32 on: February 27, 2014, 01:35:34 PM »
Ooops, typo: 999,999,997
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Offline Twilight Rose

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Re: The Wondrous Sequence (Competition)!
« Reply #33 on: February 27, 2014, 07:35:51 PM »
Yay I did good =3
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Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #34 on: February 27, 2014, 10:33:30 PM »
I bow to your mastery Twilight Rose!


*curtsies*


:D
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Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #35 on: March 23, 2014, 12:56:45 PM »
Quote from: Trixsie Vixen on February 27, 2014, 01:35:34 PM
Ooops, typo: 999,999,997

I didn't see this whoops!

The amount of steps is 361! Good job Trixsie! It's very high but still not number 1, but you're number 2 again!
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(int(e-x^2, x = -infinity..infinity))2 = Pi


We fight, we recruit, we are the anthropomorphic army. FDF forever!

$_ = "gntusbovueqrmwkradehijqr"; tr/a-z/lad hijacked under stop sign!/; print $_, "\n";
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