Author Topic: The Wondrous Sequence (Competition)!  (Read 3539 times)

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Offline anoni

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The Wondrous Sequence (Competition)!
« on: February 21, 2014, 03:26:49 PM »
Here's a mathematics game! It's more of a competition and it's pretty simple, essentially all you have to do is give a number between 1 and 1,000,000,000. Simple right!

Ok there is more to this game, it's based on this sequence which essentially goes like this. I get a number, if the number is even I divide it by 2, if the number is odd I multiply it by 3 and add it by 1. I keep doing this to the number until it reaches 1. The person who gives the number that takes the MOST steps to get to 1 wins!

Here's an example
Spoiler for Hidden:
Poster 1 = 16

Quote
Steps:
1. 16 / 2 = 8 (16 is even)
2. 8 / 2 = 4 (8 is even)
3. 4 / 2 = 2 (4 is even)
4. 2 / 2 = 1 (2 is even)

Therefore 4 steps

Poster 2 = 17

Quote
Steps:

1. 17*3 + 1 = 52 (17 is odd)
2. 52 / 2 = 26 (52 is even)
3. 26 / 2 = 13 (26 is even)
4. 13*3 + 1 = 40 (13 is odd)
5. 40 / 2 = 20 (40 is even)
6. 20 / 2 = 10 (20 is even)
7. 10 / 2 = 5 (10 is even)
8. 5*3 + 1 = 16 (5 is odd)
9. 16 / 2 = 8 (16 is even)
10. 8 / 2 = 4 (8 is even)
11. 4 / 2 = 2 (4 is even)
12. 2 / 2 = 1 (2 is even)
12 steps!

In this case, poster 2 is winning because he guessed a number that required 12 steps, while poster 1 only guessed a number that requires 4 steps (and these numbers only differed by 1!). SO yeah, the aim of the game is to find the number between 1 - 1,000,000,000 that has the most steps (hint: It's not 1,000,000,000). You can either guess, or actually try and find an educated solution. But this has been a problem with mathematicians for years and still remains unsolved, whether a number exists that will never get to 1.

I will keep a high score, whoever gets "number 1" gets my appreciation!

High Score:
  1. Twilight Rose: 392 steps
  2. Trixsie: 361 steps
  3. Bandal: 294 steps
  4. Nic: 291 steps
  5. MrRazot: 130 steps

(Also don't worry, you don't have to figure out the steps, just post a number here and I'll tell you the steps (either by replying or just updating the high score list))
« Last Edit: March 23, 2014, 12:57:06 PM by anoni »
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(int(e-x^2, x = -infinity..infinity))2 = Pi


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Offline MrRazot

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Re: The Wondrous Sequence (Competition)!
« Reply #1 on: February 21, 2014, 08:09:52 PM »
982,451,653

This is my answer :|
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Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #2 on: February 21, 2014, 10:45:47 PM »
79 steps, (you can guess as many times as you like)
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(int(e-x^2, x = -infinity..infinity))2 = Pi


We fight, we recruit, we are the anthropomorphic army. FDF forever!

$_ = "gntusbovueqrmwkradehijqr"; tr/a-z/lad hijacked under stop sign!/; print $_, "\n";

Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #3 on: February 22, 2014, 06:10:50 AM »
27,472,747


What say you?

Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #4 on: February 22, 2014, 02:54:56 PM »
going for a small number I see!

Well you shouldn't be disappointed, you have 131 steps, so you're winning :D-

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(int(e-x^2, x = -infinity..infinity))2 = Pi


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$_ = "gntusbovueqrmwkradehijqr"; tr/a-z/lad hijacked under stop sign!/; print $_, "\n";

Offline Bandal

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Re: The Wondrous Sequence (Competition)!
« Reply #5 on: February 22, 2014, 11:05:55 PM »
Let's try 67,867,967  :)
A monoculture never thrives :3

Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #6 on: February 23, 2014, 12:28:32 AM »
Good guess Bandal, that's 184 steps, that puts you in the lead! :D
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(int(e-x^2, x = -infinity..infinity))2 = Pi


We fight, we recruit, we are the anthropomorphic army. FDF forever!

$_ = "gntusbovueqrmwkradehijqr"; tr/a-z/lad hijacked under stop sign!/; print $_, "\n";

Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #7 on: February 23, 2014, 04:15:16 AM »
77,777,777


That's a weird looking number.  Maybe it's Hebrew?

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Re: The Wondrous Sequence (Competition)!
« Reply #8 on: February 23, 2014, 04:42:18 AM »
838,838,838


Cus I like 8's and 3's

Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #9 on: February 24, 2014, 06:25:15 AM »
Trixsie: 228 steps. Congratz to be the first over the 200 mark!

Nic: 291 steps (holy crap)

It's extremely coincidental that every new guess has been larger than the last xD
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(int(e-x^2, x = -infinity..infinity))2 = Pi


We fight, we recruit, we are the anthropomorphic army. FDF forever!

$_ = "gntusbovueqrmwkradehijqr"; tr/a-z/lad hijacked under stop sign!/; print $_, "\n";

Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #10 on: February 24, 2014, 11:33:55 AM »
Ha!


In that case 777,777,777


MWAH HAH HAH HAH HAH!!!


!L!I!G!H!T!N!I!N!G!

Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #11 on: February 24, 2014, 11:57:18 AM »
Adding another digit! Lets see what happens

115 steps!

Yeah I know, you'd think adding another digit would make it bigger, but this thing is ESSENTIALLY random. For example 7 has more steps than 17 xD

(Also the largest I've ever gotten was about 350, but that's me doing quite a bit of guesses)
« Last Edit: February 24, 2014, 12:01:15 PM by anoni »
  • Avatar by: WingedZephyr
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(int(e-x^2, x = -infinity..infinity))2 = Pi


We fight, we recruit, we are the anthropomorphic army. FDF forever!

$_ = "gntusbovueqrmwkradehijqr"; tr/a-z/lad hijacked under stop sign!/; print $_, "\n";

Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #12 on: February 24, 2014, 11:59:13 AM »
This means a gradual increase in hostilities!!


88 keys

Offline anoni

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Re: The Wondrous Sequence (Competition)!
« Reply #13 on: February 24, 2014, 12:01:58 PM »
The number 88?

Only has 17 steps
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(int(e-x^2, x = -infinity..infinity))2 = Pi


We fight, we recruit, we are the anthropomorphic army. FDF forever!

$_ = "gntusbovueqrmwkradehijqr"; tr/a-z/lad hijacked under stop sign!/; print $_, "\n";

Offline Trixsie Vixen

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Re: The Wondrous Sequence (Competition)!
« Reply #14 on: February 24, 2014, 12:05:57 PM »
99,988.877


*chases tail*

 

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